By Guido Cornini
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No, you don’t have to move it around between both stacks all the time and you don’t have to use ’I’ out of its context. There is a well-established word, which does the same thing: ’R@’. This is an example of the use of ’R@’: : delete >r #lag + r@ - #lag r@ negate r# +! #lead + swap cmove r> blanks ; ( ( ( ( ( ( ( ( n --) a1) a1 a2 a1 a2 a1 a2 a1 a2 a1) --) n2) n2 n3) n2) n2 a3) ’R@’ copies the top of the Return Stack to the Data Stack. This example is taken from a Forth-editor. It deletes "n" characters left of the cursor.
Since that value is removed from the Return Stack when ’LOOP’ is encountered, it doesn’t do much harm. LOOP, but we have to clean up the mess, before we encounter ’LOOP’. LOOP But we still have to be prepared that the word ’I’ will not provide the expected result (which is the current value of the counter). In fact, ’I’ does simply copy the topmost value on the Return Stack. Which is usually correct, unless you’ve manipulated the Return Stack yourself. Note that there are other words beside ’I’, which do exactly the same thing: copy the top of the Return Stack.
If you enter any other number, it will return only the integer part. You can fix this by scaling the number. However, scaling it by 10 will get you nowhere, since "3" is the square root of "9", but "30" is not the square root of "90". In that case, we have to scale it by 100, 10,000 or even 1,000,000 to get a correct answer. 4 To acquire greater precision we have to scale it up even further, like 10,000. 49" brings us even closer to the correct answer. 8. 8 65 Recursion Yes, but can she do recursion?